Wu Experiment — parity violation in ⁶⁰Co β decay
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⁶⁰Co(5⁺) → ⁶⁰Ni*(4⁺) + e⁻ + νe W(θ) ∝ 1 + A·P·(v/c)·cos θ, A(⁶⁰Co) ≈ −1 Rₛ/Rwarm = 1 + s·A·P·⟨v/c⟩·Q 𝒜 = (R↓ − R↑)/(R↓ + R↑) = −A·P·⟨v/c⟩·Q P = B₅(C/T) = 0.00
W is the relative emission probability. θ is the angle from the spin-alignment direction. A is the decay asymmetry coefficient, P is the degree of spin alignment, v is the electron speed, and c is the speed of light. Rₛ is the rate for field direction s, Rwarm is the warm-source rate, and Q accounts for the detector's finite size.
Here s is +1 for B ↑ and −1 for B ↓, and 𝒜 is the field-flip asymmetry. B₅ is the spin-5 Brillouin function, T is the crystal temperature, and C is chosen so P = 0.60 at 3 mK. ⁶⁰Ni* emits 1173.2 keV and 1332.5 keV gamma rays as it reaches its ground state. Gamma detectors are not included in this model.
Emission angle relative to the nuclear-spin direction. Bars: simulated electrons; line: expected distribution.