In a circle with centre

MATHEMATICS · Multi-part · CBSE · Mathematics · Circles · Circles

Problem

In a circle with centre OO, points AA and BB are fixed on the circumference. The chord ABAB subtends an angle of 8x∘8x^{\circ} at the centre. A point CC is chosen on the minor arc ABAB so that ∠ACB=(3x+8)∘\angle ACB = (3x + 8)^{\circ}, and a point DD is chosen on the major arc ABAB so that ∠ADB=(10x+68)∘\angle ADB = (10x + 68)^{\circ}. (i) Prove that x=8x = 8. (ii) Hence calculate the measures of ∠AOB\angle AOB, ∠ACB\angle ACB and ∠ADB\angle ADB. (iii) Determine the reflex angle ∠AOB\angle AOB. (iv) Verify that ∠ACB+∠ADB=180∘\angle ACB + \angle ADB = 180^{\circ} and explain why this result holds for any choice of points CC and DD on the two arcs of ABAB.

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