The function is given by

MATHEMATICS · Single correct · A Level · Mathematics · Algebra and Functions · Algebra and Functions

Problem

The function f:R→Rf:\mathbb R\to\mathbb R is given by f(x)=x2f(x)=x^{2}. A relation gg is formed by interchanging xx and yy in y=f(x)y=f(x), yielding g(x)=xg(x)=\sqrt{x}. Which statement correctly explains why f∘gf\circ g does NOT equal the identity on R\mathbb R? (a) Because ff is not one–one on R\mathbb R, its inverse is not a function, so f∘gf\circ g cannot be the identity. (b) Because gg is defined only for x≥0x\ge 0, the composition f∘gf\circ g is defined only for x≥0x\ge 0 and thus is not the identity on all of R\mathbb R. (c) Because taking the square root gives two possible values ±x\pm\sqrt{x}, gg is not single-valued, so the composition cannot recover xx. (d) Because f(g(x))=(x)2=∣x∣f(g(x))=(\sqrt{x})^{2}=|x|, the composition equals the absolute value of xx, not xx itself.

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