Which expression equals for a particle whose position in Cartesian coordinates is…

MATHEMATICS · Single correct · AP · AP Precalculus · Trigonometric and Polar Functions · Trigonometric and Polar Functions

Problem

Which expression equals dxdt\dfrac{dx}{dt} for a particle whose position in Cartesian coordinates is given by x=rcos⁡θx=r\cos\theta and y=rsin⁡θy=r\sin\theta, where r=r(θ)r=r(\theta) and θ=θ(t)\theta=\theta(t)? (a) −rsin⁡θ dθdt-r\sin\theta\,\dfrac{d\theta}{dt} (b) (drdθcos⁡θ−rsin⁡θ)\left(\dfrac{dr}{d\theta}\cos\theta - r\sin\theta\right) (c) (drdθcos⁡θ−rsin⁡θ)dθdt\left(\dfrac{dr}{d\theta}\cos\theta - r\sin\theta\right)\dfrac{d\theta}{dt} (d) (drdθcos⁡θ+rsin⁡θ)dθdt\left(\dfrac{dr}{d\theta}\cos\theta + r\sin\theta\right)\dfrac{d\theta}{dt}

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