For , consider the series _ n=2 ^ (-1)^ n-1 n n^ p , where is a positive constant.…

MATHEMATICS · Single correct · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

For n≥2n\ge 2, consider the series ∑n=2∞(−1)n−1ln⁡nnp,\sum_{n=2}^{\infty} (-1)^{n-1} \frac{\ln n}{n^{p}}, where pp is a positive constant. For which of the following values of pp does the series converge conditionally but not absolutely? (a) p=32p=\dfrac{3}{2} (b) p=43p=\dfrac{4}{3} (c) p=12p=\dfrac12 (d) p=2p=2

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