A block of mass rests on a rough horizontal table

PHYSICS · Multi-part · CBSE · Physics · Laws of Motion · Laws of Motion

Problem

A block of mass mm rests on a rough horizontal table. The coefficients of friction between the block and the table are μs\mu_s (static) and μk\mu_k (kinetic), with μs>μk\mu_s > \mu_k. A horizontal force FF is applied to the block. Answer the questions below. (i) Derive an expression for the minimum horizontal force F1F_1 required to just start the motion of the block. (ii) Once the block has started moving, derive an expression for the horizontal force F2F_2 that must be applied to keep it moving with uniform velocity. (iii) Show that F2<F1F_2 < F_1 and explain physically why this inequality holds. (iv) For a 10 kg10\,\text{kg} block with μs=0.42\mu_s = 0.42 and μk=0.30\mu_k = 0.30 (take g=9.8 m s−2g = 9.8\,\text{m\,s}^{-2}), calculate F1F_1 and F2F_2.

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