Transform the equation to parallel axes through the point becomes then

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

Transform the equation x2−3xy+11x−12y+36=0x^2 - 3xy + 11x - 12y + 36 = 0 to parallel axes through the point (−4,1)(-4, 1) becomes ax2+bxy+1=0ax^2 + bxy + 1 = 0 then b2−a=b^2 - a = (1) 14\frac{1}{4} (2) 116\frac{1}{16} (3) 164\frac{1}{64} (4) 1256\frac{1}{256}

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