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Transform the equation to parallel axes through the point becomes then
MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections
Problem Transform the equation x 2 − 3 x y + 11 x − 12 y + 36 = 0 x^2 - 3xy + 11x - 12y + 36 = 0 x 2 − 3 x y + 11 x − 12 y + 36 = 0 to parallel axes through the point ( − 4 , 1 ) (-4, 1) ( − 4 , 1 ) becomes a x 2 + b x y + 1 = 0 ax^2 + bxy + 1 = 0 a x 2 + b x y + 1 = 0 then b 2 − a = b^2 - a = b 2 − a =
(1) 1 4 \frac{1}{4} 4 1
(2) 1 16 \frac{1}{16} 16 1
(3) 1 64 \frac{1}{64} 64 1
(4) 1 256 \frac{1}{256} 256 1
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