The velocity of a particle in the - plane at time is v =(2t i +3t^2 j ) m/s

PHYSICS · Multi-part · CBSE · Physics · Motion in a Plane · Motion in a Plane

Problem

The velocity of a particle in the xx-yy plane at time tt is v=(2ti^+3t2j^) m/s.\mathbf{v}=(2t\hat{i}+3t^2\hat{j})\text{ m/s}. At t=0t=0, the particle starts from the coordinates (2 m,4 m)(2\text{ m},4\text{ m}). Find: (a) The acceleration of the particle at t=1 st=1\text{ s}. (b) The position vector and coordinates of the particle at t=2 st=2\text{ s}.

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