Which one of the following expressions gives the vertical displacement of a projectile

PHYSICS · Single correct · CBSE · Physics · Motion in a Plane · Motion in a Plane

Problem

Which one of the following expressions gives the vertical displacement

y

of a projectile, launched from the origin with initial speed

v_0

at an angle

\theta_0

to the horizontal, in terms of the horizontal displacement

x

and acceleration due to gravity

g

? (a)

y = x\tan\theta_0 - \dfrac{g x^2}{2 v_0^2 \sin^2\theta_0}

(b)

y = x\tan\theta_0 - \dfrac{g x^2}{v_0^2 \cos^2\theta_0}

(c)

y = x\tan\theta_0 - \dfrac{g x^2}{2 v_0^2 \cos^2\theta_0}

(d)

y = x\tan\theta_0 + \dfrac{g x^2}{2 v_0^2 \cos^2\theta_0}