The equation of the locus of points equidistant from and is

MATHEMATICS · Single correct · GCSE · Mathematics · Geometry and Measures · Geometry and Measures

Problem

The equation of the locus of points equidistant from (−1,−1)(-1,-1) and (4,2)(4,2) is (1) 3x−5y−7=03x-5y-7=0 (2) 5x+3y−9=05x+3y-9=0 (3) 4x+3y+2=04x+3y+2=0 (4) x−3y+5=0x-3y+5=0

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