Consider h(x)= cases x^ 2 +1, & x<3 [4pt] 2x-2, & x 3 cases On

MATHEMATICS · Subjective · A Level · Mathematics · Algebra and Functions · Algebra and Functions

Problem

Consider h(x)={x2+1,x<32x−2,x≥3h(x)= \begin{cases} x^{2}+1, & x<3\\[4pt] 2x-2, & x\ge 3 \end{cases} On [1,5][1,5], can the Intermediate Value Theorem be applied to guarantee a value cc such that h(c)=8h(c)=8? Answer "yes" or "no" and give a brief reason.

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