For the parametric equations and with

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

For the parametric equations x=f(t)x=f(t) and y=g(t)y=g(t) with f′(t)≠0f'(t)\neq0, the expression for the first derivative dydx\dfrac{dy}{dx} is (a) dydt dxdt\dfrac{dy}{dt}\,\dfrac{dx}{dt} (b) f′(t)g′(t)\dfrac{f'(t)}{g'(t)} (c) g′(t)f′(t)\dfrac{g'(t)}{f'(t)} (d) g′(t)−f′(t)g'(t)-f'(t)

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