MATHEMATICS · Single correct · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series
Problem
Determine the behavior of the series n=2∑∞n(lnn)31.
(a) The series converges conditionally but not absolutely.
(b) Because lnn grows slower than any power of n, the series behaves like a harmonic series, so it diverges.
(c) The series converges, because the associated improper integral from 2 to ∞ is finite.
(d) Using ∫2∞x(lnx)3dx=ln(lnx)2∞=∞, the series must diverge.