Determine the behavior of the series .

MATHEMATICS · Single correct · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

Determine the behavior of the series ∑n=2∞1n(ln⁡n)3\displaystyle\sum_{n=2}^{\infty} \frac{1}{n(\ln n)^3}. (a) The series converges conditionally but not absolutely. (b) Because ln⁡n\ln n grows slower than any power of nn, the series behaves like a harmonic series, so it diverges. (c) The series converges, because the associated improper integral from 22 to ∞\infty is finite. (d) Using ∫2∞ ⁣dxx(ln⁡x)3=ln⁡(ln⁡x)∣2∞=∞\displaystyle\int_{2}^{\infty}\!\frac{dx}{x(\ln x)^3}=\ln(\ln x)\big|_{2}^{\infty}=\infty, the series must diverge.

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