A differentiable function is defined on the open interval by h(x)=x^ 3 -6x^ 2 +9x

MATHEMATICS · Multi-part · CBSE · Mathematics · Applications of Derivatives · Applications of Derivatives

Problem

A differentiable function hh is defined on the open interval (0,4)(0,4) by h(x)=x3−6x2+9x.h(x)=x^{3}-6x^{2}+9x. Use the information below to analyze the extrema of hh and to explore how the interval on which a function is defined influences the existence of absolute extrema. (a) Describe the difference between a local (relative) extremum and an absolute (global) extremum of a function. (b) Determine every local maximum and local minimum value of hh on the open interval (0,4)(0,4) and the xx–values at which they occur. (c) Does hh attain an absolute maximum value or an absolute minimum value on (0,4)(0,4)? Provide a complete explanation that references both the results of part (b) and the conditions required by the Extreme Value Theorem.

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