PHYSICS · Multi-part · CBSE · Physics · Electrostatic Potential and Capacitance · Electrostatic Potential and Capacitance
Problem
Between two large, parallel metal plates separated by 5.0cm, the electric potential varies with vertical position y according to the quadratic relation
V(y)=200−20y+0.50y2
where V is in volts and y is in centimeters. The lower plate is at y=0cm and the upper plate is at y=5.0cm. Assume edge effects are negligible.
(a) Determine the vertical position(s) between the plates where the magnitude of the electric field is zero. Show all work leading to your answer.
(b) A small oil droplet of charge +1.6×10−19C is released from rest at y=1.0cm. Calculate the initial electric force (magnitude and direction) acting on the droplet.
(c) Compare the electric field magnitude at y=1.0cm with that at y=4.0cm. Explain how this comparison is reflected in the shape of the potential function.
(d) Suppose the potential function is adjusted so that V(y) becomes perfectly linear with the same values at the plates (V=200V at y=0 and V=185V at y=5.0cm). Describe qualitatively how the motion of the same oil droplet released at y=1.0cm would differ from its motion in the original quadratic potential. Support your answer with reasoning tied to the electric field profile.