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The vapour pressure of two volatile liquid mixtures is (in cm of Hg)
CHEMISTRY · Single correct · CBSE · Chemistry · Solutions · Solutions
Problem
The vapour pressure of two volatile liquid mixtures is
P
T
=
5.3
+
2
X
B
P_T = 5.3 + 2X_B
P
T
=
5.3
+
2
X
B
(in cm of Hg), where
X
B
X_B
X
B
is mole fraction of
B
B
B
is mixture. What is the ratio of
X
A
X_A
X
A
and
X
B
X_B
X
B
in vapour phase? (1)
73
53
\frac{73}{53}
53
73
(2)
73
53
×
P
A
′
P
B
′
\frac{73}{53} \times \frac{P_A'}{P_B'}
53
73
×
P
B
′
P
A
′
(3)
53
73
\frac{53}{73}
73
53
(4)
53
73
×
P
B
′
P
A
′
\frac{53}{73} \times \frac{P_B'}{P_A'}
73
53
×
P
A
′
P
B
′
Related theory
Raoult's Law
Solutions
Vapour Pressure of Liquid Solutions
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