The vapour pressure of two volatile liquid mixtures is (in cm of Hg)

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Problem

The vapour pressure of two volatile liquid mixtures is PT=5.3+2XBP_T = 5.3 + 2X_B (in cm of Hg), where XBX_B is mole fraction of BB is mixture. What is the ratio of XAX_A and XBX_B in vapour phase? (1) 7353\frac{73}{53} (2) 7353×PA′PB′\frac{73}{53} \times \frac{P_A'}{P_B'} (3) 5373\frac{53}{73} (4) 5373×PB′PA′\frac{53}{73} \times \frac{P_B'}{P_A'}

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