Determine whether the series converges or diverges.

MATHEMATICS · Single correct · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

Determine whether the series ∑n=1∞n2(n3+4)4/3\displaystyle \sum_{n=1}^{\infty}\frac{n^{2}}{\bigl(n^{3}+4\bigr)^{4/3}} converges or diverges. (a) The series diverges because, for large nn, its terms behave like 1/n1/31/n^{1/3}, and p<1p<1. (b) The series converges because, for large nn, its terms behave like 1/n21/n^{2}, a pp-series with p>1p>1. (c) The series diverges for the same reason that the harmonic series ∑1/n\sum 1/n diverges. (d) The series fails the nnth-term test for convergence since lim⁡n→∞n2(n3+4)4/3≠0\displaystyle\lim_{n\to\infty}\frac{n^{2}}{(n^{3}+4)^{4/3}}\neq 0."

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