XCl2 (excess) + YCl2 → XCl4 + Y ↓; YO [>400^ ] 1 2 O_2 + Y Ore of Y would be :

CHEMISTRY · Single correct · CBSE · Chemistry · Metals and Non-metals · Metals and Non-metals

Problem

XCl₂ (excess) + YCl₂ → XCl₄ + Y ↓;

YO \xrightarrow[>400^{\circ}]{\Delta} \frac{1}{2} O_2 + Y

Ore of Y would be : (1) Siderite (2) Cinnabar (3) Malachite (4) Hornsilver