Consider a general right circular cone of height and base radius

MATHEMATICS · Multi-part · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

Consider a general right circular cone of height HH and base radius RR. Suppose the cone is partially filled with a liquid to a depth hh (where 0<h<H0<h<H). The liquid drains through an opening at the tip, and at a particular instant the volume of liquid is decreasing at the constant rate kk (in units of volume per unit time). Let rr be the radius of the liquid surface corresponding to depth hh. (a) Explain why rh=RH\dfrac{r}{h}=\dfrac{R}{H} for any instantaneous depth hh. (b) Using part (a), express the volume VV of the liquid solely in terms of hh, RR, and HH, without resorting to numerical substitution. (c) By differentiating implicitly with respect to time, write a general formula for dhdt\dfrac{dh}{dt} in terms of hh, RR, HH, and kk. Do not substitute numerical values. (d) Describe how the magnitude of dhdt\dfrac{dh}{dt} changes as the liquid depth decreases toward zero, assuming kk remains constant. Provide a conceptual explanation based on the geometry of the cone.

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