For upward motion under resistance

PHYSICS · Subjective · AP · Physics C: Mechanics · Force and Translational Dynamics · Force and Translational Dynamics

Problem

For upward motion under resistance, the time of ascent is Ta=ug+F/mT_a=\frac{u}{g+F/m}; for downward motion through the same height HH, the time of descent is Td=2Hg−F/mT_d=\sqrt{\frac{2H}{g-F/m}}. Based on these expressions only, determine the correct comparison between TdT_d and TaT_a.

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