Consider a reaction whose slow elementary step is

CHEMISTRY · Subjective · A Level · Chemistry · Rate equations · Rate equations

Problem

Consider a reaction whose slow elementary step is A(g)+2 B(g)→productsA(g) + 2\,B(g) \rightarrow \text{products}, so that rate=k[A][B]2\text{rate} = k[A][B]^2. An experiment is conducted with initial concentrations [A]0=0.10 M[A]_0 = 0.10\,\text{M} and [B]0=0.20 M[B]_0 = 0.20\,\text{M}. In a second trial, [A][A] is tripled and [B][B] is halved. By what numerical factor does the initial rate in the second trial differ from that in the first?

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