The region bounded by the curves and for is revolved about the horizontal line

MATHEMATICS · Single correct · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

The region bounded by the curves y=x2y = x^{2} and y=2xy = 2x for 0≤x≤20 \le x \le 2 is revolved about the horizontal line y=−3y = -3. Which integral represents the volume of the resulting solid? (a) ∫02π[(2x)2−(x2)2] dx\displaystyle \int_{0}^{2} \pi\bigl[(2x)^{2} - (x^{2})^{2}\bigr]\,dx (b) ∫02π[(2x−x2)2] dx\displaystyle \int_{0}^{2} \pi\bigl[(2x - x^{2})^{2}\bigr]\,dx (c) ∫02π[(2x+3)2−(x2+3)2] dx\displaystyle \int_{0}^{2} \pi\bigl[(2x + 3)^{2} - (x^{2} + 3)^{2}\bigr]\,dx (d) ∫02π[(x2+3)2−(2x+3)2] dx\displaystyle \int_{0}^{2} \pi\bigl[(x^{2} + 3)^{2} - (2x + 3)^{2}\bigr]\,dx

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