The reaction of an alpha particle with beryllium is given below.

CHEMISTRY · Multi-part · US High School · Chemistry · Atomic Structure & Nuclear · Atomic Structure & Nuclear

Problem

The reaction of an alpha particle with beryllium is given below. 49Be+24He  →  ?  +01n^{9}_{4}\mathrm{Be} + ^{4}_{2}\mathrm{He} \;\rightarrow\; ? \; + ^{1}_{0}\mathrm{n} (i) Write the symbol of the product nucleus. (ii) Using the following atomic masses, calculate the QQ-value of the reaction. 49Be:  9.012182 u^{9}_{4}\mathrm{Be}:\;9.012182\,\text{u} 24He:  4.002603 u^{4}_{2}\mathrm{He}:\;4.002603\,\text{u} 612C:  12.000000 u^{12}_{6}\mathrm{C}:\;12.000000\,\text{u} 01n:  1.008665 u^{1}_{0}\mathrm{n}:\;1.008665\,\text{u} (Take 1 u=931.5 MeV1\,\text{u}=931.5\,\text{MeV}.)

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