The eccentricity of the hyperbola ( x^ 2 9 - y^ 2 16 =1 ) is

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

The eccentricity of the hyperbola x29−y216=1\dfrac{x^{2}}{9}-\dfrac{y^{2}}{16}=1 is (a) 54\dfrac{5}{4} (b) 73\dfrac{7}{3} (c) 53\dfrac{5}{3} (d) 43\dfrac{4}{3}

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