A free hydrogen atom after absorbing a photon of wavelength gets excited from the…

PHYSICS · Single correct · AP · Physics 2: Algebra-based · Modern Physics · Modern Physics

Problem

A free hydrogen atom after absorbing a photon of wavelength λa\lambda_a gets excited from the state n=1n=1 to the state n=4n=4 . Immediately after that the electron jumps to n=mn=m state by emitting a photon of wavelength λe\lambda_e . Let the change in momentum of atom due to the absorption and the emission are Δpa\Delta p_a and Δpe\Delta p_e , respectively. If λa/λe=15\lambda_a / \lambda_e = \frac{1}{5} , which of the option(s) is/are correct? [Use hc=1242hc = 1242 eV nm; 1 nm=10−9 m1 \text{ nm} = 10^{-9} \text{ m} , hh and cc are Planck's constant and speed of light, respectively] (1) Δpa/Δpe=12\Delta p_a / \Delta p_e = \frac{1}{2} (2) The ratio of kinetic energy of the electron in the state n=mn=m to the state n=1n=1 is 14\frac{1}{4} (3) m=2m=2 (4) λe=418 nm\lambda_e = 418 \text{ nm}

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