A free hydrogen atom after absorbing a photon of wavelength gets excited from the…
PHYSICS · Single correct · AP · Physics 2: Algebra-based · Modern Physics · Modern Physics
Problem
A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n=1 to the state n=4 . Immediately after that the electron jumps to n=m state by emitting a photon of wavelength λe . Let the change in momentum of atom due to the absorption and the emission are Δpa and Δpe , respectively. If λa/λe=51 , which of the option(s) is/are correct? [Use hc=1242 eV nm; 1 nm=10−9 m , h and c are Planck's constant and speed of light, respectively]
(1) Δpa/Δpe=21
(2) The ratio of kinetic energy of the electron in the state n=m to the state n=1 is 41
(3) m=2
(4) λe=418 nm