Let h(x)= cases (1+2x)-2x x^ 2 , & x<0

MATHEMATICS · Single correct · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

Let

h(x)= \begin{cases} \dfrac{\ln(1+2x)-2x}{x^{2}}, & x<0,\\ mx+n, & x\ge 0, \end{cases}

where

m

and

n

are real constants. If

h

is continuous at

x=0

, what is the value of

n

? (a)

-1

(b)

-2

(c)

0

(d)

2