Two identical point charges of magnitude are fixed on the x-axis at and

PHYSICS · Single correct · AP · Physics 2: Algebra-based · Electric Force Field and Potential · Electric Force Field and Potential

Problem

Two identical point charges of magnitude +q+q are fixed on the x-axis at x=−d2x=-\tfrac{d}{2} and x=+d2x=+\tfrac{d}{2}. What is the net electric field at the origin? (a) 8kqd2, toward the +x-axis\dfrac{8kq}{d^{2}},\ \text{toward the }+x\text{-axis} (b) 2kqd2, toward the +x-axis\dfrac{2kq}{d^{2}},\ \text{toward the }+x\text{-axis} (c) Zero, because the fields are equal in magnitude and opposite in direction. (d) kqd2, toward the +y-axis\dfrac{kq}{d^{2}},\ \text{toward the }+y\text{-axis}

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