For a series circuit with ,

PHYSICS · Single correct · CBSE · Physics · Alternating Current · Alternating Current

Problem

For a series R ⁣L ⁣CR\!L\!C circuit with R=40 ΩR=40\,\Omega, L=0.20 HL=0.20\,\text{H}, C=100 μFC=100\,\mu\text{F} and frequency 50 Hz50\,\text{Hz}, the magnitude of the impedance is closest to (a) 71 Ω71\,\Omega (b) 40 Ω40\,\Omega (c) 51 Ω51\,\Omega (d) 81 Ω81\,\Omega

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