Show dimensionally that is dimensionally correct

PHYSICS · Subjective · A Level · Physics · Measurements and their errors · Measurements and their errors

Problem

Show dimensionally that Y=mgLπr2ΔlY=\frac{mgL}{\pi r^2\Delta l} is dimensionally correct, where YY is Young's modulus of the wire material, LL is the length of the wire, mgmg is the applied weight, rr is the radius of the wire, and Δl\Delta l is the increase in its length.

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