The minimum value of function on is equal to

MATHEMATICS · Single correct · AP · Calculus AB · Analytical Applications of Differentiation · Analytical Applications of Differentiation

Problem

The minimum value of function f(x)=3x4−8x3+12x2−48x+25f(x) = 3x^4 - 8x^3 + 12x^2 - 48x + 25 on [0,3][0, 3] is equal to (a) 25 (b) -39 (c) -25 (d) 39

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