A particle moves along the parabolic path in such a way that the -component of its…

PHYSICS · Single correct · AP · Physics C: Mechanics · Kinematics · Kinematics

Problem

A particle moves along the parabolic path x=y2+2y+2x=y^2+2y+2 in such a way that the yy-component of its velocity remains 5 m s−15\ \text{m s}^{-1} during the motion. The magnitude of the acceleration of the particle is: (1) 50 m s−250\ \text{m s}^{-2} (2) 100 m s−2100\ \text{m s}^{-2} (3) 102 m s−210\sqrt{2}\ \text{m s}^{-2} (4) 0.1 m s−20.1\ \text{m s}^{-2}

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