For depths that are small compared with the Earth’s radius

PHYSICS · Single correct · CBSE · Physics · Gravitation · Gravitation

Problem

For depths dd that are small compared with the Earth’s radius RR, which expression gives the acceleration due to gravity gdg_d at that depth in terms of the surface value gg? (a) gd=g(1−2dR)g_d = g\left(1-\dfrac{2d}{R}\right) (b) gd=g(1+dR)g_d = g\left(1+\dfrac{d}{R}\right) (c) gd=g(1−d2R)g_d = g\left(1-\dfrac{d}{2R}\right) (d) gd=g(1−dR)g_d = g\left(1-\dfrac{d}{R}\right)

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