At 1 atm, 25.0 g of ice at −10 °C is converted to steam at 120 °C
PHYSICS · Single correct · A Level · Physics · Further mechanics and thermal physics · Further mechanics and thermal physics
Problem
At 1 atm, 25.0 g of ice at −10 °C is converted to steam at 120 °C. Using the data below, calculate the total amount of heat, in kilojoules, required for the entire process.
Data (assume temperature-independent):
• Specific heat capacity of ice = 2.09 J g⁻¹ °C⁻¹
• Specific heat capacity of liquid water = 4.18 J g⁻¹ °C⁻¹
• Specific heat capacity of steam = 2.01 J g⁻¹ °C⁻¹
• Molar enthalpy of fusion = 6.01 kJ mol⁻¹
• Molar enthalpy of vaporization = 40.7 kJ mol⁻¹
• Molar mass of H₂O = 18.0 g mol⁻¹
(a) 68.5kJ
(b) 78.5kJ
(c) 76.9kJ
(d) 58.7kJ