Function is continuous on

MATHEMATICS · Single correct · CBSE · Mathematics · Applications of Integrals · Applications of Integrals

Problem

Function pp is continuous on [0,5][0,5], positive on (0,2)(0,2), and negative on (2,5)(2,5). Which of the following best describes the value of ∫05p(x) dx\displaystyle \int_{0}^{5} p(x)\,dx ? (a) It equals the sum of the absolute areas of the two regions, so it must be positive. (b) It is negative because the interval where pp is below the axis is longer, so the negative area must outweigh the positive. (c) It equals the area above the xx–axis on (0,2)(0,2) minus the area below the xx–axis on (2,5)(2,5). (d) It is zero because the positive and negative areas cancel whenever the function changes sign.

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