A block rests on the floor of an elevator that is moving upward with a constant…

PHYSICS · Multi-part · CBSE · Physics · Laws of Motion · Laws of Motion

Problem

A 5.0 kg5.0\,\text{kg} block rests on the floor of an elevator that is moving upward with a constant acceleration of 2.0 m s−22.0\,\text{m}\,\text{s}^{-2}. Because of vibrations, the block slides relative to the floor during the motion. Coefficient of kinetic friction between the block and the elevator floor: μk=0.35\mu_k = 0.35 A horizontal force of 25 N25\,\text{N} directed toward the right is applied to the block while it is sliding. Assume the elevator’s interior is large enough that contact with walls is not a factor. (a) Determine the magnitude of the normal force exerted on the block by the elevator floor while the elevator accelerates upward. (b) Calculate the magnitude of the kinetic friction force acting on the block. (c) Find the magnitude and direction of the block’s acceleration relative to the elevator’s frame while the 25 N25\,\text{N} horizontal force is acting.

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