The ground-state electron of a doubly ionised lithium atom ( , ) is to be removed…

CHEMISTRY · Multi-part · CBSE · Chemistry · Structure of Atom · Structure of Atom

Problem

The ground-state electron of a doubly ionised lithium atom (Li2+\mathrm{Li}^{2+}, Z=3Z = 3) is to be removed completely from the atom. (a) Calculate the ionisation energy per atom in eV\text{eV}. (b) Express the result of part (a) in kJ mol−1\mathrm{kJ\,mol}^{-1}. (Avogadro number NA=6.02×1023 mol−1N_A = 6.02 \times 10^{23}\,\text{mol}^{-1}, 1 eV=1.60×10−19 J1\,\text{eV} = 1.60 \times 10^{-19}\,\text{J}.) (c) By what factor is the value obtained in part (b) greater than the corresponding value for He+\mathrm{He}^{+}? (Use your answer to part (b) and quote the numerical factor only.)

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