The activation energy of in equilibrium for the forward reaction is whereas for the…

CHEMISTRY · Subjective · A Level · Chemistry · Rate equations · Rate equations

Problem

The activation energy of H2+I2⇌2HIH_2 + I_2 \rightleftharpoons 2HI in equilibrium for the forward reaction is 167 kJ mol−1167 \text{ kJ mol}^{-1} whereas for the reverse reaction is 180 kJ mol−1180 \text{ kJ mol}^{-1} . The presence of catalyst lowers the activation energy by 80 kJ mol−180 \text{ kJ mol}^{-1} . Assuming that the reactions are made at 27∘C27^\circ C and the frequency factor for forward and backward reactions are 4×10−44 \times 10^{-4} and 2×10−32 \times 10^{-3} respectively, calculate KCK_C .

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