Two different gas-phase processes can be used to convert sulfur dioxide into sulfur…

CHEMISTRY · Multi-part · A Level · Chemistry · Chemical equilibria (Le Chatelier’s principle and Kc) · Chemical equilibria (Le Chatelier’s principle and Kc)

Problem

Two different gas-phase processes can be used to convert sulfur dioxide into sulfur trioxide, an important intermediate in the production of sulfuric acid. Process A: 2 SO2(g)+O2(g)⇌2 SO3(g)2\,SO_2(g) + O_2(g) \rightleftharpoons 2\,SO_3(g) KA=9.2×103K_A = 9.2 \times 10^{3} at 700 K700\,\text{K} Process B: SO2(g)+12 O2(g)⇌SO3(g)SO_2(g) + \frac{1}{2}\,O_2(g) \rightleftharpoons SO_3(g) KB=95K_B = 95 at 700 K700\,\text{K} (operates in the presence of a different catalyst and reactor design) Assume ideal-gas behavior and identical reactant feed compositions (stoichiometric proportions) for both processes. Answer the following questions. (a) For each process, describe qualitatively the relative amounts of SO2SO_2, O2O_2, and SO3SO_3 present at equilibrium. (b) Identify which process is expected to deliver the higher percent yield of SO3SO_3 under the stated conditions, and justify your answer using the given equilibrium constants. (c) Briefly explain why a manufacturer might still consider implementing the process with the lower equilibrium constant.

Related theory

Browse the problem library