In quadrilateral

MATHEMATICS · Single correct · CBSE · Mathematics · Circles · Circles

Problem

In quadrilateral ABCDABCD, ∠B=(3y+20)∘\angle B = (3y + 20)^\circ and ∠D=(7y−40)∘\angle D = (7y - 40)^\circ. If ABCDABCD is cyclic, calculate ∠B\angle B. (a) 100∘100^{\circ} (b) 65∘65^{\circ} (c) 80∘80^{\circ} (d) 68∘68^{\circ}

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