CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

ddx[sin⁡nxcos⁡(nx)]=\frac{d}{dx}\left[\sin^n x\cos(nx)\right]= (1) nsin⁡n−1xcos⁡((n+1)x)n\sin^{n-1}x\cos((n+1)x) (2) nsin⁡n−1xcos⁡(nx)n\sin^{n-1}x\cos(nx) (3) nsin⁡n−1xcos⁡((n−1)x)n\sin^{n-1}x\cos((n-1)x) (4) nsin⁡n−1xsin⁡((n+1)x)n\sin^{n-1}x\sin((n+1)x)

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