At a certain temperature

CHEMISTRY · Single correct · A Level · Chemistry · Chemical equilibria (Le Chatelier’s principle and Kc) · Chemical equilibria (Le Chatelier’s principle and Kc)

Problem

At a certain temperature, the equilibrium constant for the forward reaction below is K0=2.0×104K_0=2.0\times10^{4}. 2P(g)⇌Q(g)+R(g)2P(g)\rightleftharpoons Q(g)+R(g) What is the equilibrium constant for the reaction written as 3Q(g)+3R(g)⇌6P(g)3Q(g)+3R(g)\rightleftharpoons6P(g) (a) K03K_0^{3} (b) 1K0\dfrac{1}{K_0} (c) (1K0)3\left(\dfrac{1}{K_0}\right)^{3} (d) K01/3K_0^{1/3}

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