Let , and A = vmatrix -2 & 4+d & ( ) - 2 1 & ( + 2) & d 5 & (2 ) - d & (- ) + 2 + 2d…

MATHEMATICS · Single correct · CBSE · Mathematics · Determinants · Determinants

Problem

Let d∈Rd \in R, and A=∣−24+d(sin⁡θ)−21(sin⁡θ+2)d5(2sin⁡θ)−d(−sin⁡θ)+2+2d∣,θ∈[0,2π]A = \begin{vmatrix} -2 & 4+d & (\sin \theta) - 2 \\ 1 & (\sin \theta + 2) & d \\ 5 & (2 \sin \theta) - d & (-\sin \theta) + 2 + 2d \end{vmatrix}, \theta \in [0, 2\pi] If the minimum value of det⁡(A)\det(A) is 8, then a value of dd is: (a) -5 (b) -7 (c) 2(2+1)2(\sqrt{2} + 1) (d) 2(2−2)2(\sqrt{2} - 2)

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