The equation of the straight line through the origin and parallel to the line and are

MATHEMATICS · Single correct · CBSE · Mathematics · Three-Dimensional Geometry · Three-Dimensional Geometry

Problem

The equation of the straight line through the origin and parallel to the line (b+c)x+(c+a)y+(a+b)z=k(b+c)x + (c+a)y + (a+b)z = k and (b−c)x+(c−a)y+(a−b)z=k(b-c)x + (c-a)y + (a-b)z = k are (1) xb2−c2=yc2−a2=za2−b2\frac{x}{b^2 - c^2} = \frac{y}{c^2 - a^2} = \frac{z}{a^2 - b^2} (2) xb=yb=za\frac{x}{b} = \frac{y}{b} = \frac{z}{a} (3) xa2−bc=yb2−ca=zc2−ab\frac{x}{a^2 - bc} = \frac{y}{b^2 - ca} = \frac{z}{c^2 - ab} (4) None of the above

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