Let the line cut the parabola at points and

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

Let the line lx+my=1lx+my=1 cut the parabola y2=4axy^2=4ax at points AA and BB. Normals at AA and BB meet at point CC. The normal from CC, other than these two, meets the parabola at DD. Then the coordinates of DD are (1) (a,2a)(a,2a) (2) (4aml2,4al)\left(\frac{4am}{l^2},\frac{4a}{l}\right) (3) (2am2l2,2al)\left(\frac{2am^2}{l^2},\frac{2a}{l}\right) (4) (4am2l2,4aml)\left(\frac{4am^2}{l^2},\frac{4am}{l}\right)

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