The function is defined by f(x)= cases kx^ 2 +3, & x=1

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

The function ff is defined by f(x)={kx2+3,x=1,x2+3,x≠1.f(x)=\begin{cases} kx^{2}+3, & x=1,\\ x^{2}+3, & x\neq 1. \end{cases} For which value of kk is ff continuous at x=1x=1, and what is lim⁡x→1f(x)\displaystyle \lim_{x\to 1} f(x)? (a) k=4,  lim⁡=4k=4,\;\lim =4 (b) k=1,  lim⁡=3k=1,\;\lim =3 (c) k=1,  lim⁡=4k=1,\;\lim =4 (d) k=0,  lim⁡=3k=0,\;\lim =3

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