A particle’s position in the ground frame is

PHYSICS · Subjective · CBSE · Physics · Motion in a Plane · Motion in a Plane

Problem

A particle’s position in the ground frame is x(t)x(t). A second frame moves along the same axis with constant velocity vrelv_{\text{rel}} relative to the ground, so the particle’s coordinate in that frame is x′(t)=x(t)−vreltx'(t)=x(t)-v_{\text{rel}}t. Show that the particle’s acceleration measured in the moving frame is equal to its acceleration measured in the ground frame.

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