A reaction obeys the rate law

CHEMISTRY · Single correct · CBSE · Chemistry · Chemical Kinetics · Chemical Kinetics

Problem

A reaction obeys the rate law rate=k[A][B]2rate = k[A][B]^2. In Experiment 1, [A]=0.20 M[A] = 0.20\,\text{M} and [B]=0.10 M[B] = 0.10\,\text{M}. In Experiment 2, [A]=0.40 M[A] = 0.40\,\text{M} and [B]=0.30 M[B] = 0.30\,\text{M}. The temperature is the same in both experiments, so kk is unchanged. By what factor does the initial rate in Experiment 2 differ from that in Experiment 1? (a) 66 (b) 33 (c) 1818 (d) 99

Related theory

Browse the problem library