Inorganic benzene reacts with HCl to form a compound

CHEMISTRY · Single correct · CBSE · Chemistry · Chemical Bonding and Molecular Structure · Chemical Bonding and Molecular Structure

Problem

Inorganic benzene reacts with HCl to form a compound B3N3H9Cl3\text{B}_3\text{N}_3\text{H}_9\text{Cl}_3. The protonation occurs at : (1) B-atom (2) N-atom (3) First at B-atom then rearranges into N-atom (4) First at N-atom then rearranges into B-atom

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