The rate of heat flow through a uniform slab of cross-sectional area

PHYSICS · Single correct · AP · Physics 2: Algebra-based · Thermodynamics · Thermodynamics

Problem

The rate of heat flow

\dfrac{dQ}{dt}

through a uniform slab of cross-sectional area

A

, thickness

L

and thermal conductivity

k

for a temperature difference

\Delta T

between its faces is proportional to (a)

\displaystyle \frac{2kA\,\Delta T}{L}

(b)

\displaystyle \frac{kA\,\Delta T}{2L}

(c)

\displaystyle \frac{kA\,\Delta T}{L}

(d)

\displaystyle \frac{3}{2}\,\frac{kA\,\Delta T}{L}