Consider with

MATHEMATICS · Single correct · CBSE · Mathematics · Vector Algebra · Vector Algebra

Problem

Consider △ABC\triangle ABC with A=(a)A = (\mathbf{a}) , B=(b)B = (\mathbf{b}) and C=(c)C = (\mathbf{c}) . If b⋅(a+c)=b⋅b+a⋅c\mathbf{b} \cdot (\mathbf{a} + \mathbf{c}) = \mathbf{b} \cdot \mathbf{b} + \mathbf{a} \cdot \mathbf{c} , ∣b−a∣=3|\mathbf{b} - \mathbf{a}| = 3 and ∣c−b∣=4|\mathbf{c} - \mathbf{b}| = 4 , then the angle between the medians AMAM and BDBD is (1) π−cos⁡−1(1513)\pi - \cos^{-1}\left(\frac{1}{5\sqrt{13}}\right) (2) π−cos⁡−1(1135)\pi - \cos^{-1}\left(\frac{1}{13\sqrt{5}}\right) (3) cos⁡−1(1513)\cos^{-1}\left(\frac{1}{5\sqrt{13}}\right) (4) cos⁡−1(1135)\cos^{-1}\left(\frac{1}{13\sqrt{5}}\right)

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